问题 解答题
(1)(2
48
-3
27
6

(2)
32
-(2+
2
2
(3)
1
2
3
÷
2
1
3
×
1
2
5

(4)-
15
8
2
10
27
÷
25
12a3

(5)
2
π
x3
+
x
2
-
x
8
-
x
3
1
x

(6)
3
3
+(-2)2×
1
8
-
3
+(
2005
-
2004
)0
答案

(1)(2

48
-3
27
)÷
6

=2

8
-3
9
2

=4

2
-
9
2
2
=-
1
2
2

(2)

32
-(2+
2
2=4
2
-4-4
2
-2=-6;

(3)

1
2
3
÷
2
1
3
×
1
2
5
=
5
3
×
3
7
×
7
5
=1;

(4)-

15
8
2
10
27
÷
25
12a3

=-

15
8
×
64
27
×
12a3
25

=-

15
8
×
8
3
×
2a
a
5

=-2a

a

(5)

2
π
x3
+
x
2
-
x
8
-
x
3
1
x

=

2x
x
π
+
2x
2
-
2x
4
-
x
3

=(

2x
π
-
1
3
x
+
2x
4

(6)

3
3
+(-2)2×
1
8
-
3
+(
2005
-
2004
0=
3
+4×
2
4
-
3
+1=
2
+1.

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