问题 填空题
(体验过程题)计算:(-5
1
10
2×2
5
×2
5

原式=(-5
1
10
2×(2
5
2
=(-5)2×(
1
10
2×______×______②
=25×______×4×______③
=______.
(1)请将上述过程补充完整.
(2)上述解答过程第①步运用了公式______,第②步运用了公式______,第③步运用了公式______.
(3)体验上述过程,请完成计算:
(-5
2
5
2×2
0.3
×(-2
3
10
)÷(-2
1
3
2
答案

(1)22,(

5
2②;

1
10
,5 ③;

50;

(2)a•a=a2,(ab)2=a2b2,(

a
2=a;

(3)(-5

2
5
2×2
0.3
×(-2
3
10
)÷(-2
1
3
2=(-5)2×(
2
5
2×2×
3
10
×(-2)×
3
10
÷
4
3

=25×

2
5
×2×
3
10
×(-2)×
3
10
×
3
4

=-25×

2
5
×4×
3
4
×
3
10

=-9.

单项选择题 A1/A2型题
问答题