问题
解答题
(1)
(2)(4b
|
答案
(1)原式=1 2
+a 3a 4
-a 7a 8
-a a 4
,a
=(
-1 2
)3a 8
;a
(2)原式=(4
+ab
)-(3ab
+3ab
)ab
=4
+ab
-3ab
-3ab ab
=-
.ab
(1)
(2)(4b
|
(1)原式=1 2
+a 3a 4
-a 7a 8
-a a 4
,a
=(
-1 2
)3a 8
;a
(2)原式=(4
+ab
)-(3ab
+3ab
)ab
=4
+ab
-3ab
-3ab ab
=-
.ab