问题 解答题
计算:
(1)
1
2
10
•(3
15
-5
6
)

(2)(
x3y
-3xy+
xy3
)÷
xy

(3)(2
3
-2
)(3
2
-3
);
(4)
12
-
3
÷(2+
3
)
答案

(1)原式=

1
2
10
×3
15
-
1
2
10
×5
6

=

3
2
10×15
-
5
2
10×6

=

15
2
6
-5
15

(2)原式=

x3y
÷
xy
-3xy÷
xy
+
xy3
÷
xy

=x-3

xy
+y.

(3)原式=2

3
×3
2
-2
3
×3-2×3
2
-2×3
2
+6

=6

6
-6
3
-6
2
+6.

(4)原式=

12
-
3
÷2-
3
÷
3

=2

3
-2
3
+3=3.

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