问题 解答题
计算:
(1)3
2
÷2
3

(2)(5
6
-4
3
)÷3
2

(3)(7
2
+2
6
)÷(2
6
-7
2
);
(4)
6
÷(3
6
-2
7
)
答案

(1)原式=

3
2
2
3
=
3
2
×
3
2
3
×
3
=
6
2

(2)原式=

5
6
-4
3
3
2
=
(5
6
-4
3
2
 
3
2
×
2
=
5
3
3
-
2
3
6

(3)原式=

7
2
+2
6
2
6
-7
2
=
(7
2
+2
6
)(2
6
+7
2
(2
6
-7
2
)2
6
+7
2
 )
=-
61
37
-
28
37
3

(4)原式=

6
3
6
-2
7
=
6
(3
6
+2
7
(3
6
-2
7
)(3
6
+2
7
=
9
13
+
42
13

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