问题
解答题
已知
(1)求
(2)若(
|
答案
(1)设
=(x,y),∴2b
+a
=(8,6)+(x,y)=(x+8,y+6)=(3,18),b
∴
,∴x+8=3 y+6=18
,∴x=5 y=12
=(-5,12),b
∴
•a
=(-5)×4+3×12=16.b
(2)由于
+ka
=(4,3)+(-5k,12k)=(4-5k,3+12k),(b
+ka
)⊥b
,a
∴(
+ka
)•b
=4(4-5k)+3(3+12k)=25+16k=0,a
∴k=-
.16 25