问题 选择题
在△ABC中,已知向量
AB
=(cos18°,cos72°),
AC
=(2cos63°,2cos27°),则∠BAC=(  )
A.450B.1350C.810D.990
答案

AB
AC
=cos18°•2cos63°+cos72°•2cos27°

=2(cos18°sin27°+sin18°cos27°)

=2sin(18°+27°)=2sin45°=

2

|

AB
|=
cos218°+cos272°
=
cos218°+sin218°
=1,

|

AC
|=
4cos263°+4cos227°
=
4(sin227°+cos227°)
=2,

故cos∠BAC=

AB
AC
|
AB
|•|
AC
|
=
2
2
,又0°≤∠BAC≤180°,

所以∠BAC=45°

故选A

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