问题 解答题
带分数除法.
(1)例:4
2
7
÷1
11
14
=
30
7
÷
25
14
=______=______
分数除法中有带分数的,先把带分数化成______,然后______.
(2)试一试.
16÷1
3
5





3
10
÷1
4
5





4
2
7
÷5





5
7
÷1
1
14
2
1
10
÷1
2
3
6
3
5
÷
3
5
1
1
5
×3
3
4
2
1
3
-
3
5
答案

(1)4

2
7
÷1
11
14
=
30
7
÷
25
14
=
30
7
×
14
25
=
12
5

(2)①16÷1

3
5
=16÷
8
5
=16×
5
8
=10;

3
10
÷1
4
5
=
3
10
÷
9
5
=
3
10
×
5
9
=
1
6

③4

2
7
÷5=
30
7
÷5=
30
7
×
1
5
=
6
7

5
7
÷1
1
14
=
5
7
÷
15
14
=
5
7
×
14
15
=
2
3

⑤2

1
10
÷1
2
3
=
21
10
÷
5
3
=
21
10
×
3
5
=
63
50

⑥6

3
5
÷
3
5
=
33
5
÷
3
5
=
33
5
×
5
3
=11;

⑦1

1
5
×3
3
4
=
6
5
×
15
4
=
9
2

⑧2

1
3
-
3
5
=
7
3
-
3
5
=
35
15
-
9
15
=
26
15

故答案为:

30
7
×
14
25
12
5
;假分数,相除.

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