问题
解答题
(1)计算:
(2)计算:|
(3)
(4)a2
|
答案
(1)原式=2
+25
-32
+45 2
=6
-2
;5
(2)原式=4-
-4+23 3
=-
+23 3
=
;3
(3)原式=
×32 3
+6×x 1 2 x
=2
+3x x
=5
;x
(4)原式=a2×2
+3a×5a2a 2a
=2a2
+15a22a 2a
=17a2
.2a
(1)计算:
(2)计算:|
(3)
(4)a2
|
(1)原式=2
+25
-32
+45 2
=6
-2
;5
(2)原式=4-
-4+23 3
=-
+23 3
=
;3
(3)原式=
×32 3
+6×x 1 2 x
=2
+3x x
=5
;x
(4)原式=a2×2
+3a×5a2a 2a
=2a2
+15a22a 2a
=17a2
.2a