问题
解答题
| 解方程： （1）2（x+1）-3（x-1）=1； （2）
|
答案
（1）去括号，得
2x+2-3x+3=1，
移项、合并同类项，得
-x=-4，
系数化为1，得
x=4；
（2）去分母，得
2（2x+1）-（5x-1）=6，
去括号，得
4x+2-5x+1=6，
移项、合并同类项，得
-x=3，
系数化为1，得
x=-3．
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| 解方程： （1）2（x+1）-3（x-1）=1； （2）
|
（1）去括号，得
2x+2-3x+3=1，
移项、合并同类项，得
-x=-4，
系数化为1，得
x=4；
（2）去分母，得
2（2x+1）-（5x-1）=6，
去括号，得
4x+2-5x+1=6，
移项、合并同类项，得
-x=3，
系数化为1，得
x=-3．
| 完形填空 | |||
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