问题
填空题
x与
|
答案
由题意可得-2x-
≥0,x+1≥0,2
∴-1≤x≤-
,则2 2
≤x2≤1,0≤1 2
≤1-x2
,x-2 2
≤0,x+1-x2
≤0,1-x2
∴原式=
-(x+
)21-x2
=-x-(x-
)21-x2
+x-1-x2
=-21-x2
,1-x2
故答案为=-2
.1-x2
x与
|
由题意可得-2x-
≥0,x+1≥0,2
∴-1≤x≤-
,则2 2
≤x2≤1,0≤1 2
≤1-x2
,x-2 2
≤0,x+1-x2
≤0,1-x2
∴原式=
-(x+
)21-x2
=-x-(x-
)21-x2
+x-1-x2
=-21-x2
,1-x2
故答案为=-2
.1-x2