问题
解答题
(1)解方程:2x2-3x-2=0 (2)计算:(
|
答案
(1)2x2-3x-2=0,
(x-2)(2x+1)=0,
x-2=0或2x+1=0,
解得:x1=2,x2=-
;1 2
(2)原式=(2
-4×3
)-(3×2 4
-2×3 3
)2 2
=2
-3
-2
+3 2
=
.3
(1)解方程:2x2-3x-2=0 (2)计算:(
|
(1)2x2-3x-2=0,
(x-2)(2x+1)=0,
x-2=0或2x+1=0,
解得:x1=2,x2=-
;1 2
(2)原式=(2
-4×3
)-(3×2 4
-2×3 3
)2 2
=2
-3
-2
+3 2
=
.3