问题 解答题
脱式计算
5845÷7+1020×5=
2150÷(104-99)=
1200-200÷5+28=250+255+260+265+270=
答案

(1)5845÷7+1020×5,

=835+5100,

=5935;

(2)2150÷(104-99),

=2150÷5,

=430;

(3)1200-200÷5+28,

=1200-40+28,

=1160+28,

=1188;

(4)250+255+260+265+270,

=250+(255+265)+(260+270),

=250+520+530,

=1300.

单项选择题
单项选择题