问题
填空题
若
|
答案
∵
(lim x→-∞
-x+k)=1,x2-x+1
∴
(lim x→-∞
-x+k)x2-x+1
=lim x→-∞ (
-x+k)(x2-x+1
+x-k) x2-x+1
+x-kx2-x+1
=lim x→-∞ (2k-1)x+1-k2
+x-kx2-x+1
=
=1,2k-1 2
∴k=
.3 2
故答案为
.3 2
若
|
∵
(lim x→-∞
-x+k)=1,x2-x+1
∴
(lim x→-∞
-x+k)x2-x+1
=lim x→-∞ (
-x+k)(x2-x+1
+x-k) x2-x+1
+x-kx2-x+1
=lim x→-∞ (2k-1)x+1-k2
+x-kx2-x+1
=
=1,2k-1 2
∴k=
.3 2
故答案为
.3 2