问题
填空题
已知S是△ABC所在平面外一点,D是SC的中点,若
|
答案
如图,D是SC的中点,故有
=BD
(1 2
+BS
)BC
=
(1 2
+BA
)+AS
(1 2
-AC
)AB
=-
+AB 1 2
+AC 1 2 AS
又由已知
=xBD
+yAB
+zAC AS
故x=-1,y=
,z=1 2 1 2
代入得x+y+z=0
故答案为 0
已知S是△ABC所在平面外一点,D是SC的中点,若
|
如图,D是SC的中点,故有
=BD
(1 2
+BS
)BC
=
(1 2
+BA
)+AS
(1 2
-AC
)AB
=-
+AB 1 2
+AC 1 2 AS
又由已知
=xBD
+yAB
+zAC AS
故x=-1,y=
,z=1 2 1 2
代入得x+y+z=0
故答案为 0