问题
解答题
计算: (1)3
(2)7
(3)
|
答案
(1)原式=3×2
-2×32
+5×42 2
=6
-62
+202 2
=20
;2
(2)原式=7
-3a
+2a a
=6
;a
(3)原式=
•(-2 b
)×2 3 1 3 ab5•a3b• a b
=-4 9b a5b5
=-
a2b4 9
.ab
计算: (1)3
(2)7
(3)
|
(1)原式=3×2
-2×32
+5×42 2
=6
-62
+202 2
=20
;2
(2)原式=7
-3a
+2a a
=6
;a
(3)原式=
•(-2 b
)×2 3 1 3 ab5•a3b• a b
=-4 9b a5b5
=-
a2b4 9
.ab