问题
选择题
|
答案
∵C22+C32+C42+…+Cn2=C33+C32+C42++Cn2=C43+C42+…+Cn2═Cn+13,
n(
+C 12
+C 13
++C 14
)=nC 1n
,(2+n)(n-1) 2
∴lim n→∞
=
+C 22
+C 23
++C 24 C 2n n(
+C 12
+C 13
++C 14
)C 1n lim n→∞
=C 3n+1 n(n-1)(n+2) 2 lim n→∞
=(n+1)n(n-1) 6 n(n-1)(n+2) 2
.1 3
故选B.