问题
选择题
|
答案
lim x→ π 2 sin2x cos(π-x)
=lim x→ π 2 2sinxcosx -cosx
=
(-2sinx)lim x→ π 2
=-2sinπ 2
=-2．
故选A．
搜题请搜索小程序“爱下问搜题”
|
lim x→ π 2 sin2x cos(π-x)
=lim x→ π 2 2sinxcosx -cosx
=
(-2sinx)lim x→ π 2
=-2sinπ 2
=-2．
故选A．