问题
解答题
(1)(y-1)2-4=0
(2)(配方法)2x2-5x+2=0.
答案
(1)移项得:(y-1)2=4,
开方得:y-1=±2,
解得:y1=3,y2=-1.
(2)x2-
5 |
2 |
x2-
5 |
2 |
5 |
4 |
5 |
4 |
(x-
5 |
4 |
9 |
16 |
x-
5 |
4 |
3 |
4 |
∴x1=
1 |
2 |
(1)(y-1)2-4=0
(2)(配方法)2x2-5x+2=0.
(1)移项得:(y-1)2=4,
开方得:y-1=±2,
解得:y1=3,y2=-1.
(2)x2-
5 |
2 |
x2-
5 |
2 |
5 |
4 |
5 |
4 |
(x-
5 |
4 |
9 |
16 |
x-
5 |
4 |
3 |
4 |
∴x1=
1 |
2 |