问题
解答题
(1)计算:2
(2)计算:2sin60°-cot30°+tan45°. (3)解方程:x2-6x+1=0. |
答案
(1)原式=10
-93
+23
=33
;3
(2)原式=2×
-3 2
+13 3
=
-3
+13 3
=2 3
+1;3
(3)原方程可转化为(x-3)2=8
即x-3=±22
∴x1=3+2
,x2=3-22
.2
(1)计算:2
(2)计算:2sin60°-cot30°+tan45°. (3)解方程:x2-6x+1=0. |
(1)原式=10
-93
+23
=33
;3
(2)原式=2×
-3 2
+13 3
=
-3
+13 3
=2 3
+1;3
(3)原方程可转化为(x-3)2=8
即x-3=±22
∴x1=3+2
,x2=3-22
.2