问题
解答题
计算: (1)定义计算“⊗”:a⊗b=|a+b|-(a-b).若(x-2)⊗(1-x)=0,求x的值. (2)求
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答案
(1)根据题意得
|(x-2)+(1-x)|-(x-2)+(1-x)=0,
1-(x-2)+(1-x)=0,
解得x=2;
(2)
x-2(x-1 2
y2)-(1 3
y2-1 3
x)3 2
=
x-2x+1 2
y2-2 3
y2+1 3
x3 2
=
y2.1 3
将y=-3代入得,原式=3.