问题 解答题
计算:
(1)3
1
2
-(-
1
3
)+(-
1
2
)+2
2
3

(2)-14-
1
6
×〔3-(-32)〕×(-2)
(3)(-
7
9
-
11
12
+
1
6
)×(-6)2
(4)-22-[2-(1+
1
3
×0.5)]÷[32-(-2)2].
答案

(1)原式=3

1
2
+
1
3
-
1
2
+2
2
3

=3

1
2
-
1
2
+
1
3
+2
2
3

=3+3

=6;

(2)原式=-1-

1
6
×(3-9)×(-2)

=-1-

1
6
×(-6)×(-2)

=-1-2

=-3;

(3)原式=(-

7
9
-
11
12
+
1
6
)×36

=-

7
9
×36-
11
12
×36+
1
6
×36

=-28-33+6

=-61+6

=-55;

(4)原式=-4-[2-(1+

1
6
)]÷[9-4]

=-4-[2-1

1
6
]÷5

=-4-

5
6
×
1
5

=-4-

1
6

=-4

1
6

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