问题
解答题
计算: (1)3
(2)-14-
(3)(-
(4)-22-[2-(1+
|
答案
(1)原式=3
+1 2
-1 3
+21 2 2 3
=3
-1 2
+1 2
+21 3 2 3
=3+3
=6;
(2)原式=-1-
×(3-9)×(-2)1 6
=-1-
×(-6)×(-2)1 6
=-1-2
=-3;
(3)原式=(-
-7 9
+11 12
)×361 6
=-
×36-7 9
×36+11 12
×361 6
=-28-33+6
=-61+6
=-55;
(4)原式=-4-[2-(1+
)]÷[9-4]1 6
=-4-[2-1
]÷51 6
=-4-
×5 6 1 5
=-4-1 6
=-4
.1 6