问题 解答题
设x=
3+
5
2
,y=
3-
5
2
,求x3+y3
答案

x+y=

3+
5
2
+
3-
5
2
=3

x•y=

3+
5
2
3-
5
2
=
9-5
4
=1

∴x3+y3=(x+y)(x2-xy+y2

=(x+y)[(x2+2xy+y2)-3xy]

=

(x+y)•[(x+y)2-3xy]

=

3•(32-3)

=18,

故答案为18.

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