问题
填空题
已知x,y为实数,且满足
|
答案
根据二次根式有意义的条件可得,y≤1,x≥-1,
∴
≥0,-(y-1)x+1
≥0,1-y
又∵
-(y-1)1+x
=0,1-y
∴
=0,-(y-1)x+1
=0,1-y
解得:x=-1,y=1,
∴x3-y3=-2.
故答案为:-2.
已知x,y为实数,且满足
|
根据二次根式有意义的条件可得,y≤1,x≥-1,
∴
≥0,-(y-1)x+1
≥0,1-y
又∵
-(y-1)1+x
=0,1-y
∴
=0,-(y-1)x+1
=0,1-y
解得:x=-1,y=1,
∴x3-y3=-2.
故答案为:-2.