问题 解答题
观察下列各式及验证过程:
1
2
-
1
3
=
1
2
2
3
,验证
1
2
-
1
3
=
1
2×3
=
2
22×3
=
1
2
2
3
1
2
(
1
3
-
1
4
)
=
1
3
3
8
,验证
1
2
(
1
3
-
1
4
)
=
1
2×3×4
=
3
32×4
=
1
3
3
8
1
3
(
1
4
-
1
5
)
=
1
4
4
15
,验证
1
3
(
1
4
-
1
5
)
=
1
3×4×5
=
4
42×5
=
1
4
4
15

(1)按照上述三个等式及其验证过程中的基本思想,猜想
1
4
(
1
5
-
1
6
)
的变形结果并进行验证.
(2)针对上述各式反映的规律,写出用n(n为任意的自然数,且n≥2)表示的等式,并给出证明.
答案

(1)

1
4
(
1
5
-
1
6
)
=
1
5
5
24

验证:

1
4
(
1
5
-
1
6
)
=
1
4×5×6
=
5
52×6
=
1
5
5
24

(2)

1
n
(
1
n+1
-
1
n+2
)
=
1
n+1
n+1
(n+1)2-1
1
n
(
1
n+1
-
1
n+2
)
=
1
n+1
n+1
n•(n+2)

验证:

1
n
(
1
n+1
-
1
n+2
)
=
1
n(n+1)(n+2)
=
n+1
n(n+1)2(n+2)
=
1
n+1
n+1
n(n+2)

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