问题 选择题
王芳7:45从家出发,8:02到学校,路上用了(  )
A.47分B.17分C.1时2分
答案

8时02分-7时45分=17分钟

答:路上用了17分钟.

故选:B.

问答题

【说明】下面的程序先构造Point类,再顺序构造Ball类。由于在类Ball中不能直接存取类Point中的xCoordinate及yCoordinate属性值,Ball中的toString方法调用Point类中的toString方法输出中心点的值。在MovingBall类的toString方法中,super.toString调用父类Ball的toString方法输出类Ball中声明的属性值。 public class Point { private double xCoordinate; private double yCoordinate; public Point 0 } public Point(ouble x, double y) { xCoordinate = x; yCoordinate = y; } public String toString() {return "( + Double.toString(Coordinate)+ ","+ Double.toString(Coordinate) + "); } //other methods } public class Ball { (1) ; //中心点 private double radius; //半径 private String colour; ///颜色 public Ball() { } public Ball(double xValue, double yValue, double r)// 具有中心点及半径的构造方法 {center= (2) ;//调用类Point 中的构造方法radius = r; } public Ball(double xValue, double yValue, double r, String c) // 具有中心点、半径及颜色的构造方法 { (3) ;//调用3个参数的构造方法 colour = c; } public String toString() { return "A ball with center" + center, toString() + ", radius"+ Double.toString(radius) + ", colour" + colour; } //other methods } public class MovingBall. (4) { private double speed; public MovingBall() { } public MovingBall(double xValue, double yValue, double r, String e, double s) { (5) ;// 调用父类Ball中具有4个参数的构造方法speed = s; } public String toString( ) { return super, toString( ) + ", speed "+ Double.toString(speed); } //other methods } public class Tester{ public static void main(String args[]){ MovingBall mb = new MovingBall(10,20,40,"green",25); System.out.println(mb); } }

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