问题 解答题
两台机床同时生产直径是40mm的零件,为了鉴别机床性能好坏,检验产品的质量,从产品抽出10件进行测量,结果如下表(单位:mm)
机床甲4039.840.140.239.94040.239.840.239.8
机床乙404039.94039.940.24040.14039.9
问哪个机床性能更好些?
答案

.
x
=
1
10
(40+39.8+40.1+40.2+39.9+40+40.2+39.8+40.2+39.8)=40mm,

.
x
=
1
10
(40+40+39.9+40+39.9+40.2+40+40.1+40+39.9)=40mm,

∴S2=

1
10
[(40-40)2+(39.8-40)2+(40.1-40)2+(40.2-40)2+(39.9-40)2+(40-40)2+(40.2-40)2+(39.8-40)2+(40.2-40)2+(39.8-40)2]=0.026(mm)2

S2=

1
10
[(40-40)2+(40-40)2+(39.9-40)2+(40.2-40)2+(40-40)2+(39.9-40)2+(40.2-40)2+(40-40)2+(40.1-40)2+(40-40)2+(39.9-40)2]=0.008(mm)2

∵S2>S2

∴乙机床的性能更好些.

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