问题
解答题
为了培养学生的环保意识,某校组织课外小组对该市进行空气含尘调查,下面是一天中每2小时测得的数据(单位:g/m3):
(2)如果对大气飘尘的要求为平均值不超过0.025 g/m3,问这天该城市的空气是否符合要求?为什么? |
答案
(1)把这组数据从小到大排列为0.01,0.01,0.02,0.03,0.03,0.03,0.03,0.03,0.04,0.04,0.04,0.05,
故中位数是0.03(g/m3).
出现次数最多的数据是0.03g/m3,所以众数是0.03g/m3.
(2)∵平均数=(0.01+0.01+0.02+0.03+0.03+0.03+0.03+0.03+0.04+0.04+0.04+0.05)÷12=0.03 (g/m3),
∵0.03 g/m3>0.025 g/m3
∴这天该城市的空气不符合要求.