问题 解答题
为了培养学生的环保意识,某校组织课外小组对该市进行空气含尘调查,下面是一天中每2小时测得的数据(单位:g/m3):
0.040.030.020.030.040.01
0.030.040.030.050.010.03
(1)求出这组数据的众数和中位数;
(2)如果对大气飘尘的要求为平均值不超过0.025 g/m3,问这天该城市的空气是否符合要求?为什么?
答案

(1)把这组数据从小到大排列为0.01,0.01,0.02,0.03,0.03,0.03,0.03,0.03,0.04,0.04,0.04,0.05,

故中位数是0.03(g/m3).

出现次数最多的数据是0.03g/m3,所以众数是0.03g/m3

(2)∵平均数=(0.01+0.01+0.02+0.03+0.03+0.03+0.03+0.03+0.04+0.04+0.04+0.05)÷12=0.03 (g/m3)

∵0.03 g/m3>0.025 g/m3

∴这天该城市的空气不符合要求.

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