问题 解答题
先观察下列等式,然后用你发现的规律解答下列问题.
1
1×2
=1-
1
2

1
2×3
=
1
2
-
1
3

1
3×4
=
1
3
-
1
4

┅┅
(1)计算
1
1×2
+
1
2×3
+
1
3×4
+
1
4×5
+
1
5×6
=______;
(2)探究
1
1×2
+
1
2×3
+
1
3×4
+…+
1
n(n+1)
=______;(用含有n的式子表示)
(3)若
1
1×3
+
1
3×5
+
1
5×7
+…+
1
(2n-1)(2n+1)
的值为
17
35
,求n的值.
答案

(1)原式=1-

1
2
+
1
2
-
1
3
+
1
3
-
1
4
+
1
4
-
1
5
+
1
5
-
1
6
=1-
1
6
=
5
6

(2)原式=1-

1
2
+
1
2
-
1
3
+
1
3
-
1
4
+
1
4
-
1
5
+…+
1
n
-
1
n+1
=1-
1
n+1
=
n
n+1

(3)

1
1×3
+
1
3×5
+
1
5×7
+…+
1
(2n-1)(2n+1)

=

1
2
(1-
1
3
)+
1
2
(
1
3
-
1
5
)+
1
2
(
1
5
-
1
7
)+…+
1
2
(
1
2n-1
-
1
2n+1
)

=

1
2
(1-
1
2n+1
)=
n
2n+1

n
2n+1
=
17
35
,解得n=17,

经检验n=17是方程的根,

∴n=17.

选择题
单项选择题