问题
解答题
用含有n的式子表示第n项: (1)2,4,6,8…, (2)1,3,5,7…, (3)3,5,7,9…, (4)1
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答案
(1)2,4,6,8…,第n项为2n;
(2)1,3,5,7…,第n项为2n-1;
(3)3,5,7,9…,第n项为2n+1;
(4)1
,21 2
,32 3
,43 4
,…第n项为n4 5
.n n+1
用含有n的式子表示第n项: (1)2,4,6,8…, (2)1,3,5,7…, (3)3,5,7,9…, (4)1
|
(1)2,4,6,8…,第n项为2n;
(2)1,3,5,7…,第n项为2n-1;
(3)3,5,7,9…,第n项为2n+1;
(4)1
,21 2
,32 3
,43 4
,…第n项为n4 5
.n n+1