问题 解答题
下面是按一定规律排列的一列数:
第1个数:a1=
1
2
-(1+
-1
2
)

第2个数:a2=
1
3
-(1+
-1
2
)(1+
(-1)2
3
)(1+
(-1)3
4
)

第3个数:a3=
1
4
-(1+
-1
2
)(1+
(-1)2
3
)(1+
(-1)3
4
)(1+
(-1)4
5
)(1+
(-1)5
6
)


第n个数:an=
1
n+1
-(1+
-1
2
)(1+
(-1)2
3
)(1+
(-1)3
4
)…(1+
(-1)2n-1
2n
)

(1) 求出a1,a2,a3
(2) 化简an=
1
n+1
-(1+
-1
2
)(1+
(-1)2
3
)(1+
(-1)3
4
)…(1+
(-1)2n-1
2n
)
答案

(1)a1=0,a2=-

1
6
,a3=-
1
4

(2)an=

1
n+1
-(1+
-1
2
)(1+
(-1)2
3
)(1+
(-1)3
4
)…(1+
(-1)2n-1
2n
),

=

1
n+1
-
1
2
×
4
3
×
3
4
×…×
2n
2n-1
×
2n-1
2n

=

1
n+1
-
1
2

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