问题
解答题
合并下列各式中的同类项: (1)3
(2)x
(3)4
|
答案
(1)3x3+x3
=(3+1)x3
=4x3.
(2)xy2-
xy21 5
=(1-
)xy21 5
=
xy2.4 5
(3)4a2+3b2+2ab-4a2-4b2
=(4-4)a2+(3-4)b2+2ab
=-b2+2ab.
合并下列各式中的同类项: (1)3
(2)x
(3)4
|
(1)3x3+x3
=(3+1)x3
=4x3.
(2)xy2-
xy21 5
=(1-
)xy21 5
=
xy2.4 5
(3)4a2+3b2+2ab-4a2-4b2
=(4-4)a2+(3-4)b2+2ab
=-b2+2ab.