问题 解答题
合并下列各式中的同类项:
(1)3
x
+
x

(2)x
y
-
1
5
x
y

(3)4
a
+3
b
+2ab-4
a
-4
b
答案

(1)3x3+x3

=(3+1)x3

=4x3

(2)xy2-

1
5
xy2

=(1-

1
5
)xy2

=

4
5
xy2

(3)4a2+3b2+2ab-4a2-4b2

=(4-4)a2+(3-4)b2+2ab

=-b2+2ab.

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