问题 解答题
合并同类项:
(1)5a-3b-a+2b;
(2)-3x2+7x-6+2x2-5a+1;
(3)a2b-b2c+3a2b+2b2c;
(4)-
1
3
a2b-
1
2
ab2+
1
6
a2b+ab2
答案

(1)原式=5a-a-3b+2b=4a-b;

(2)原式=-3x2+2x2+7x-5a-6+1=x2+7x-5a-5;

(3)原式=a2b+3a2b-b2c+2b2c=4a2b+b2c;

(4)原式=-

1
3
a2b+
1
6
a2b-
1
2
ab2+ab2=-
1
6
a2b+
1
2
ab2

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