根据表格数据可推知所用凸透镜的焦距f满足
| 次序 | 蜡烛到凸透镜的距离 | 像的性质 |
| 1 | 26cm | 倒立缩小的实像 |
| 2 | 20cm | 倒立放大的实像 |
| 3 | 6cm | 正立放大的虚像 |
答案：B
题目分析：当物距为26cm时成倒立缩小的实像，所以26cm＞2f，则f＜13cm．
当物距为20cm时，成倒立放大的实像，所以f＜20cm＜2f，则10cm＜f＜20cm．
当物距为6cm时，成正立放大的虚像，所以6cm＜f，则f＞6cm．
综合得出：10cm＜f＜13cm．
故选B．
点评：此题考查了对凸透镜成像规律的应用，有关凸透镜成像的规律一定要熟练掌握．
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