写出下列程序的运行结果 [11] 。 #include＜iostream. h＞ void func(double x, int &part1, double &part2){part1=int(x)+500:part2=(x+500-part1)*100; } void main( ){int n;double x, f;x=1001. 0103;func (x, n, f):cout＜＜"Part 1="＜＜n＜＜" , part2="＜＜f＜＜end1 }