问题
解答题
设全集I={2,3,x2+2x-3},A={5},CIA={2,y},求x,y的值.
答案
∵A={5},I={2,3,x2+2x-3},A⊆I,∴5∈I,
∴x2+2x-3=5即x2+2x-8=0,解得x=-4或x=2.
∴I={2,3,5},∵y∈CIA,∴y∈I,且y∉A,即y≠5,
又由CIA中元素的互异性知:y≠2,∴y=3.
综上:x=-4或x=2;y=3.
设全集I={2,3,x2+2x-3},A={5},CIA={2,y},求x,y的值.
∵A={5},I={2,3,x2+2x-3},A⊆I,∴5∈I,
∴x2+2x-3=5即x2+2x-8=0,解得x=-4或x=2.
∴I={2,3,5},∵y∈CIA,∴y∈I,且y∉A,即y≠5,
又由CIA中元素的互异性知:y≠2,∴y=3.
综上:x=-4或x=2;y=3.