问题
选择题
设集合A={x|y=lg(1-x)},集合B={y|y=x2},则A∩B=( )
A.(-∞,1)
B.(-∞,1]
C.[0,1]
D.[0,1)
答案
由A={x|y=lg(1-x)}
∵1-x>0
解得:x<1
∴A={x|x<1}
由集合B={y|y=x2},
∵x2≥0
∴B={y|y≥0}
∴A∩B={x|x<1}∩{y|y≥0}=[0,1)
故答案为:D
设集合A={x|y=lg(1-x)},集合B={y|y=x2},则A∩B=( )
A.(-∞,1)
B.(-∞,1]
C.[0,1]
D.[0,1)
由A={x|y=lg(1-x)}
∵1-x>0
解得:x<1
∴A={x|x<1}
由集合B={y|y=x2},
∵x2≥0
∴B={y|y≥0}
∴A∩B={x|x<1}∩{y|y≥0}=[0,1)
故答案为:D
用方框内的单词完成下面的句子(有多余选项)。 | |
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