问题 解答题
已知ax2+bx+1与2x2-3x+1的积不含x3和x项,试计算下面代数式的值.
1
(a-1)(b-1)
+
1
ab
+
1
(a+1)(b+1)
+
1
(a+2)(b+2)
+…+
1
(a+2010)(b+2010)
答案

(ax2+bx+1)•(2x2-3x+1),

=2ax4-3ax3+ax2+2bx3-3bx2+bx+2x2-3x+1,

=2ax4+(-3a+2b)x3+(a-3b+2)x2+(b-3)x+1,

∵不含x3和x项,

∴b-3=0,-3a+2b=0,

∴b=3,a=2,

把a=2,b=3代入得:

1
(a-1)(b-1)
+
1
ab
+
1
(a+1)(b+1)
+
1
(a+2)(b+2)
+…+
1
(a+2010)(b+2010)

=

1
1×2
+
1
2×3
+
1
3×4
+
1
4×5
+…+
1
2012×2013

=

1
1
-
1
2
+
1
2
-
1
3
+
1
3
-
1
4
+
1
4
-
1
5
+…+
1
2012
-
1
2013

=1-

1
2013

=

2012
2013

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