问题
解答题
①计算:(x+1)(2x+3)
②因式分2x2-8y2.
答案
①(x+1)(2x+3),
=2x2+3x+2x+3,
=2x2+5x+3;
②2x2-8y2,
=2(x2-4y2),
=2(x+2y)(x-2y).
①计算:(x+1)(2x+3)
②因式分2x2-8y2.
①(x+1)(2x+3),
=2x2+3x+2x+3,
=2x2+5x+3;
②2x2-8y2,
=2(x2-4y2),
=2(x+2y)(x-2y).