问题
解答题
计算下列各题:
(1)(4x+1)(x-3)
(2)已知a+b=2,ab=-3,求a2+b2的值.
答案
(1)(4x+1)(x-3)=4x2-12x+x-3=4x2-11x-3.
(2)∵a+b=2,ab=-3,
∴a2+b2=(a+b)2-2ab=22-2×(-3)=4+6=10.
计算下列各题:
(1)(4x+1)(x-3)
(2)已知a+b=2,ab=-3,求a2+b2的值.
(1)(4x+1)(x-3)=4x2-12x+x-3=4x2-11x-3.
(2)∵a+b=2,ab=-3,
∴a2+b2=(a+b)2-2ab=22-2×(-3)=4+6=10.