问题
填空题
计算(1-
|
答案
原式=(
-x+1 x+1
)•(x-1)(x+1)x-1 x+1
=
•(x-1)(x+1)x+1-x+1 x+1
=
•(x-1)(x+1)2 x+1
=2(x-1).
故答案为=2(x-1).
计算(1-
|
原式=(
-x+1 x+1
)•(x-1)(x+1)x-1 x+1
=
•(x-1)(x+1)x+1-x+1 x+1
=
•(x-1)(x+1)2 x+1
=2(x-1).
故答案为=2(x-1).