问题
解答题
设1995x3=1996y3=1997z3,且
求
|
答案
设1995x3=1996y3=1997z3=k(k≠0),
∴1995=
,1996=k x3
,1997=k y3
,k z3
代入已知得
=3
+k x
+k y k z
+3 k x3
+3 k y3
,3 k z3
即
?3 k
=3
+1 x
+1 y 1 z
(3 k
+1 x
+1 y
),1 z
由k≠0,xyz>0,可知x>0,y>0,z>0,
∴
=3
+1 x
+1 y 1 z
+1 x
+1 y
,1 z
故原式=1.