问题
填空题
已知ab=1,则(
|
答案
∵ab=1,
∴
+1 a+1
=1 b+1
=a+b+2 ab+a+b+1
=1,a+b+2 a+b+2
则(
+1 a+1
)2013=1.1 b+1
故答案为:1
已知ab=1,则(
|
∵ab=1,
∴
+1 a+1
=1 b+1
=a+b+2 ab+a+b+1
=1,a+b+2 a+b+2
则(
+1 a+1
)2013=1.1 b+1
故答案为:1