问题
解答题
已知:x+y+z≠0,a、b、c均不为0,且
|
答案
先把a=
代入x y+z
中得,a 1+a
=a 1+a
=x y+z 1+ x y+z
,x x+y+z
同理可得
=b 1+b
,y x+y+z
=c 1+c
,z x+y+z
∴
+a 1+a
+b 1+b
=c 1+c
+x x+y+z
+y x+y+z
=1.z x+y+z
答:所求式子的答案是1.
已知:x+y+z≠0,a、b、c均不为0,且
|
先把a=
代入x y+z
中得,a 1+a
=a 1+a
=x y+z 1+ x y+z
,x x+y+z
同理可得
=b 1+b
,y x+y+z
=c 1+c
,z x+y+z
∴
+a 1+a
+b 1+b
=c 1+c
+x x+y+z
+y x+y+z
=1.z x+y+z
答:所求式子的答案是1.