问题
解答题
先化简,再求值:(1+
|
答案
原式=
÷x+1 x x2-1 x
=
÷x+1 x (x+1)(x-1) x
=
•x+1 x x (x+1)(x-1)
=
,1 x-1
当x=
时,原式=2
=1
-12
+1.2
先化简,再求值:(1+
|
原式=
÷x+1 x x2-1 x
=
÷x+1 x (x+1)(x-1) x
=
•x+1 x x (x+1)(x-1)
=
,1 x-1
当x=
时,原式=2
=1
-12
+1.2