问题
解答题
已知实数a满足a2+2a-8=0,求
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答案
-1 a+1
×a+3 a2-1 a2-2a+1 a2+4a+3
=
-1 a+1
×a+3 (a+1)(a-1)
,(a-1)2 (a+3)(a+1)
=
-1 a+1
,a-1 (a+1)2
=a+1-(a-1) (a+1)2
=
,2 (a+1)2
由a2+2a-8=0知,(a+1)2=9,
∴
=2 (a+1)2
,2 9
即
-1 a+1
×a+3 a2-1
的值为a2-2a+1 a2+4a+3
.2 9