问题
解答题
(1)解方程:2x2-5x+2=0; (2)已知|a-2|+
|
答案
(1)∵2x2-5x+2=0
∴(x-2)(2x-1)=0
解得x1=2,x2=
;1 2
(2)∵|a-2|+
=0,b-3
∴a-2=0,b-3=0
∴a=2,b=3;
原式=
=a(a+b)•a(a-b) b2(a-b)(a+b)
=a2 b2
.4 9
(1)解方程:2x2-5x+2=0; (2)已知|a-2|+
|
(1)∵2x2-5x+2=0
∴(x-2)(2x-1)=0
解得x1=2,x2=
;1 2
(2)∵|a-2|+
=0,b-3
∴a-2=0,b-3=0
∴a=2,b=3;
原式=
=a(a+b)•a(a-b) b2(a-b)(a+b)
=a2 b2
.4 9