问题 解答题
先化简,再求值:(
1
x2-2x
-
1
x2-4x+4
2
x2-2x
,其中x=1.
答案

原式=[

1
x(x-2)
-
1
(x-2)2
x(x-2)
2

=

1
x(x-2)
×
x(x-2)
2
-
1
(x-2)2
×
x(x-2)
2

=

1
2
-
x
2(x-2)

=

x-2
2(x-2)
-
x
2(x-2)

=

1
2-x

当x=1时,原式=

1
2-1
=1.

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