问题
填空题
若{x|x2-(a+1)x+b=0}={1,-3},则a=______,b=______.
答案
因为{x|x2-(a+1)x+b=0}={1,-3},
所以
,12-(a+1)×1+b=0 (-3)2-(a+1)(-3)+b=0
解得a=-3,b=-3,
故答案为:-3;-3.
若{x|x2-(a+1)x+b=0}={1,-3},则a=______,b=______.
因为{x|x2-(a+1)x+b=0}={1,-3},
所以
,12-(a+1)×1+b=0 (-3)2-(a+1)(-3)+b=0
解得a=-3,b=-3,
故答案为:-3;-3.