问题
解答题
已知x=2009+
|
答案
÷(x-x-y x
)2xy-y2 x
=
÷(x-y x
-x2 x
)2xy-y2 x
=
÷x-y x x2-2xy+y2 x
=
•x-y x x (x-y)2
=
,1 x-y
当x=2009+
,y=2010时,原式=2
=1 2009+
-20102
=1
-12
+1.2
已知x=2009+
|
÷(x-x-y x
)2xy-y2 x
=
÷(x-y x
-x2 x
)2xy-y2 x
=
÷x-y x x2-2xy+y2 x
=
•x-y x x (x-y)2
=
,1 x-y
当x=2009+
,y=2010时,原式=2
=1 2009+
-20102
=1
-12
+1.2